2006-09-28 02:58:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
this process is basicly useless now that we have computers/calculators which do it much faster.
They don't have to be large numbers.
basicly, it is just log(A * B) = log(A)+log(B)
so A*B = antilog(log(A) + log(B))
If you have a slide rule or a table of logs, this is useful. otherwise, just pull out your calculator.
2006-09-28 03:02:19 · answer #1 · answered by Peter L 2 · 0⤊ 0⤋
In case you couldnt tell by the above answers, logs basically just change multiplication into addition. Instead of multiplying huge numbers, we can add them and take the antilog and it will be the product of the two numbers. Very cool.
2006-09-28 04:31:38 · answer #2 · answered by James 1 · 0⤊ 0⤋
You reduce each number to an exponent and a mantissa and find the log of the mantissa then add the logs and find the number corresponding to the resulting mantissa then move the decimal point according to the resulting exponent.
example: 3723 times 45 . 4 +log .3723 + 2 + log .45
2006-09-28 03:32:26 · answer #3 · answered by Fredrick Carley 2 · 0⤊ 0⤋
consider the example,
36978*45634
log36978*45634=log36978+log45634
search the tables and find out the logs, add them up and finally take the antilog!!!
2006-09-28 03:03:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋
given: a, and b are large numbers, and y is their product
show: how logs could be used to determine the product
y = a * b
log(y) = log( a * b )
log(y) = log(a) + log(b)
exp(log(y))=exp(log(a)+log(b))
y = exp( log(a) + log(b) )
Be cautious, this is an approximation. There is roundoff.
2006-09-28 03:05:20 · answer #5 · answered by Curly 6 · 1⤊ 0⤋