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i have a total of 3 guys that want me to go out with them. one of them i really want to date but i am currently with one of the others. i have thought about my options and still nothing comes to mind. can u help me?

2006-09-27 13:22:14 · 6 answers · asked by jessiejaneskid 1 in Family & Relationships Singles & Dating

6 answers

Go out with all three and decide who you like best then go out with them again and see if you still like oine the best then ask them to meet your parents and see who they like best. If you and your parents agree on your choice then he be the one for you.

2006-09-27 13:24:54 · answer #1 · answered by Totoru 5 · 0 0

You need to be honest to yourself about your feelings. First of all, if you are already with someone, you need to let him know that you are no longer going to be able to be committed to the relationship. You don't want to be labeled as a cheater, right? If you are really interested in this other guy, give it a chance but don't try and get the best of both worlds. One or the other.

2006-09-27 20:28:16 · answer #2 · answered by super_mom 2 · 0 0

play the game of luck... add the names in a basket and the first to get 2 out of 3 means that person gets first.

2006-09-27 20:24:21 · answer #3 · answered by duckfangs34534 1 · 0 0

Can't u casually date? Does all dating mean that sex is always involved? Your not going to marry any of them yet, are u? Don't put all yr eggs in one basket, unless it's serious.

I'm NoT Talking ABout THOSE EGGS!

2006-09-27 20:26:50 · answer #4 · answered by regwoman123 4 · 0 0

The name of the game is choose. Be a big girl and make a decision concerning who you want to be with, and get on with your life.

2006-09-27 20:24:35 · answer #5 · answered by Special K 5 · 0 0

It's easy. If you don't want to be with the one you're with, break up with him. It would be uncool and disrespectful all the way around (meaning toward your boyfriend, the other guy, and even yourself) to go out with him on the sly.

2006-09-27 20:25:55 · answer #6 · answered by Laura Renee 6 · 0 0

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