2006-09-26 03:38:24 · 2 answers · asked by EC-S 3 in Science & Mathematics ➔ Engineering
To be more specific . . . what is the likelihood that non-axial stresses experienced by a compression spring under normal use with deform the spring in such a manner that they cause the spring to become more (or less) square?
Is it reasonable to assume that this will happen? Or are the non-axial forces generally not strong enough to significantly deform a spring in this manner?
2006-09-26 04:04:42 · update #1
I image that creep would enter into this discussion somewhere. If this was a factor I would then question if the creep was evenly distributed or concentrated.
2006-09-26 05:15:31 · answer #1 · answered by baudeagle 4 · 0⤊ 0⤋
It would seem reasonable that "fatigue" would play a role in any material you use in anything! Springs in a motor vehicle would be a great example. You don't have to abuse the vehicle for the springs to become "weak"! It's a natural process of the material they are made from-"fatigue"! My only degree is "common sense"!
2006-09-26 10:49:06 · answer #2 · answered by Anonymous · 0⤊ 1⤋