you know like: 3.1415914159... etc. except wayyy longer. lol
2006-09-25 21:56:21 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It is proved that Pi is irrational, meaning there is no periodicity of the digits. However there may be some other pattern. Here is a transcendental (worse than irrational) number for which there is a pattern in digits:
X=10^{-1}+10^{-10}+10^{-10^10}+10^{-10^{10^10}}+...., then we have
X=0.10000000010....(10 billion zeros)...010...(10^{ten billion zeros})....01..... . It is not hard to see that this number can not be algebraic but it has a nice pattern. On the other hand I don't think (but not sure), that it is even known that any given number among 0,1,2,...,9 repeats infinitely often times in the expansion of Pi.
2006-09-26 04:33:14 · answer #1 · answered by firat c 4 · 0⤊ 0⤋
If a numbers decimal expansion starts to cycle, then the number is rational. Since it is known that pi is irrational, this never happens. Now, it is *possible* that there is some other type of pattern in the digits, but none has been found. It is suspected that in some technical sense the digits are random (that is, that every finite pattern occurs as often as its length would suggest), but that has not been shown.
2006-09-26 10:53:54 · answer #2 · answered by mathematician 7 · 0⤊ 0⤋
I have seen pi figured out to a million digits. I am sure there are people who have gone further. To date, it is still classified as a non-repreating, non-terminating decimal number.
However, for a fun representation of the first couple dozen digits, visit the source below. It's pretty cool, but may cause one to think: Wow, someone had waaay too much time on their hands.
2006-09-26 05:07:23 · answer #3 · answered by quntmphys238 6 · 0⤊ 0⤋
It can be proven that Pi is not a rational number, so it does not have repeated patterns, however, theoretically, it could be computed up to any desired accuracy (given the necessary computational power).
2006-09-26 05:41:03 · answer #4 · answered by ted 3 · 0⤊ 0⤋
That's the beauty of irrationality, NO pattern can occur in the infinite decimal series. Totally random! Amazing yeah?
Try,
http://www.math.clemson.edu/~simms/neat/math/pi/piproof.html
http://www.lrz-muenchen.de/~hr/numb/pi-irr.html
http://www.maa.org/pubs/monthly_may97_toc.html
2006-09-26 07:19:27 · answer #5 · answered by yasiru89 6 · 0⤊ 0⤋
No. Pi is a non-terminating non-repeating decimal. If pi had a pattern it would be repeating.
2006-09-26 09:07:12 · answer #6 · answered by SmileyGirl 4 · 0⤊ 0⤋
Nope
2006-09-26 05:37:11 · answer #7 · answered by yogen p 2 · 0⤊ 0⤋
Nope
2006-09-26 04:58:45 · answer #8 · answered by teef_au 6 · 0⤊ 0⤋
Yes, each digit appears roughly 10 percent of the time.
2006-09-26 08:13:53 · answer #9 · answered by uselessadvice 4 · 0⤊ 0⤋
Unfortunately no because this is irrational number and irrational number does not have pattern.
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2006-09-26 06:31:53 · answer #10 · answered by Mein Hoon Na 7 · 0⤊ 0⤋