I have to find the force, in the direction of motion of a car, which the seat produces on the back of the passenger at maximum acceleration.
2006-09-25 20:28:28 · 8 answers · asked by jeanpace89 1 in Education & Reference ➔ Homework Help
Force=mass*accelaretion
= 80*10=800kgm/sec^2
2006-09-25 20:33:24 · answer #1 · answered by Fred 2 · 1⤊ 0⤋
The simple way is to discount gravity altogether, and just apply the F = m x a equation, where
F = 80 x 10m/s²
F = 800N
However, if you take into account the earth's gravity's effect on the passenger, assuming that the car is travelling on flat ground at 0 incline, you'll find that the resultant force doesn't act in the direct opposite direction to the car (ie: not directly into the back of the car seat), but diagonally down and back. I find that it's easiest to determine this by drawing a little force diagram, using the forces in Newton scale.
For example, let's take the scale as 1cm to represent 100N (where a line of 1cm length represents 100N of force). Let's round the earth's gravity to 10m/s², so the force felt by the passenger due to gravity is 10 x 80 = 800N. Draw a vertical line down 8cm long. The force felt by the passenger due to the car's accelleration is 10 x 80 = 800N; draw a horizontal line 8cm long from the end of the first line. Draw a diagonal line from the starting point of the first line to the end point of the second line.
The length of the diagonal line is the resultant force acting on the passenger due to the car's accelleration and the earth's gravity. The direction of the line (from the starting point of the first line to the end point of the second line) represents the direction of the same resultant force.
From this, you'll find that the resultant force is 1.131kN acting diagonally down and in the opposite direction to that of the car.
2006-09-25 20:47:21 · answer #2 · answered by k² 6 · 0⤊ 0⤋
The car is actually irrelevent as are the other answers intimating the car mass, frictional force incline etc as necessary inputs.
The only important fact is that force is a VECTOR being applied to the passenger by the seat.
1. State your positive and negative directions by arrows (presumably the car is going forward (+ve) - but to a maths/physics teacher this is NOT taken for granted). SO STATE IT and show it in a diagram by arrows else you will lose marks.
2. As already stated in other answers, the force will then be 800 Newtons
The previous answer taking into account gravity resulting in a diagonal downward vector is technically correct - but if your teacher/tutor hasn't specified this in the question - you can probably ignore it
2006-09-26 07:57:22 · answer #3 · answered by Bill N 3 · 0⤊ 0⤋
An acceleration of 10m/s^2 are you sure?
Sounds like the car has been chucked off an aeroplane. That rate of acceleration is the same for an object in freefall.
2006-09-25 20:50:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Force = mass * acceleration
The answer is 800 Newtons
2006-09-25 20:31:28 · answer #5 · answered by gbiaki 2 · 0⤊ 0⤋
How about considering your OWN homework? Having somebody else do it for you (like on here......) is commonly known as cheating.
2006-09-25 20:51:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋
this is an incomplete question ...
1. weight of the car is not provided
2. you have not what is frictional facter of the surface and tyre
2006-09-25 20:37:33 · answer #7 · answered by bigchiefygun 2 · 0⤊ 3⤋
Just stop with questions.......brain can't handle it..........just don't have the power.........grey matter seeping out of ears........noooooooooooooooooooooooooooooooooo!
2006-09-25 20:32:16 · answer #8 · answered by The Dude 2 · 0⤊ 1⤋