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Question

A rocket that went 600 ft was 127 MPH, what would speed of the rocket that went 2000 Ft high be?

Does the speed directly influence height?

They used the same engines

Answer 1

Here's how to figure the height, given the initial vertical velocity.

1. Express the initial velocity in feet per second (60 mph is 88 ft/sec, so you can use that proportion to convert a speed given in mph).

2. Divide the initial velocity by 32 ft/sec^2 to determine the number of seconds it will take for gravity to slow the rocket down to a zero vertical velocity.

3. Calculate that number of seconds times the average velocity (which will be half of the initial velocity, since the rocket is slowing down linearly from initial velocity to zero). The product is the maximum height (in feet) that the rocket will travel.

But if you know the maximum height a rocket traveled (or how high you would like for it to travel), you can calculate the initial velocity as follows:

1. Take the square root of the maximum height.
2. Multiply the result by 8 to get the initial velocity in ft/sec.
3. If desired, convert to mph by multiplying by 60/88.

Hope that's what you need.

Incidentally, I calculate that the 127mph rocket should rise to 542 feet, and that a rocket would have to start at 358 ft/sec (or 244 mph) to reach 2000 feet.

Answer 2

In air, the answer is complicated by air resistance. However, if the 2 rockets had the same engine, they had the same energy, burn time, and force. Since one went over 3 times as high, it probably had less than 1/3 the weight. E=mgh) If it had 1/3 the weight it accelerated at 3 times the rate. (F=ma). So the velocity would be about 3 times as much, v=at.

Answer 3

Depends