2 people play the game. One gets odds, and the other gets even. Players choose how many fingers, if any, to throw out. If the total count is even, then that person wins. If it is odd, then that is the person to win. Can be one time, or two out of three.
Hope this answer helps you.
2006-09-25 18:29:17
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answer #1
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answered by anthony c 3
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It's sort of like rock, paper, scissors in that it is a game that helps 2 or more people come to a mutual agreement. One person picks odds the other evens. On the count of 3 you pound your hand and show a certain number of fingers. If you add the amount shown on all 4 hands and it's odd then odd man gets it.
2006-09-26 01:29:44
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answer #2
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answered by starmoishe 4
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You just throw out an amount of fingers...whoever is highest wins.
One person can only play ODDS, while the other plays EVENS. That is my guess.
Kind of like rock, paper, scissors.
2006-09-26 01:30:31
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answer #3
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answered by Gothic Martha™ 6
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It's like rock, paper, scissors. The point is you really aren't conscious of how many fingers you throw out there if you're doing it fast.
2006-09-26 01:29:54
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answer #4
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answered by dbackbarb 4
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the total sum of the fingers if its even he wins if its odd the other guy wins
2006-09-26 01:29:26
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answer #5
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answered by -^-Smooth C-^- 4
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it's like scissor paper stone
2006-09-26 01:29:48
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answer #6
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answered by oneblondepilgrim 6
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well i really dont know
2006-09-26 01:25:19
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answer #7
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answered by Anonymous
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