-[2-(3-x)]=2{3-2[4-2(2-x)]}
2006-09-25 17:14:34 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
can you please show me how to get the answer and explain it as simple as possible, my daughter still does not understand, thank you
2006-09-25 17:18:29 · update #1
17
2006-09-25 17:16:21 · answer #1 · answered by casperenrag 2 · 0⤊ 0⤋
You multiply it out, starting with the innermost parentheses: Left side is -[2-3+x] = -[-1+x] =1-x
Right side is 2*{3-2[4-4+2x]} = 2*{3-2*[2x]} = 2*{3-4x} = 6-8x
1-x = 6-8x
7x = 5
x=5/7
2006-09-26 00:23:37 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
-[2-3+x] = 2 {3-2[4-4+2x]}
-2+3-x = 2 {3-8+8-4x}
-2+3-x = 2 {3-4x}
-2+3-x = 6-8x
1-x = 6-8x
+x = +x
1 = 6-7x
-6 = -6
-5 = -7x
-5/-7 = x
x= 5/7
hope this is right and it helps
good luck
2006-09-26 00:24:43 · answer #3 · answered by krissy 2 · 0⤊ 0⤋
-2+3-x=2{3-2(4-4+x)}
1-x=2{3-2x}
1-x=6-4x
4x-x=6-1
3x=5
x=5/3
2006-09-26 00:18:41 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋