I would like to know the what, when, where, why, and how of the Krebs Cycle - in plain english rather than biological terms.
2006-09-25 17:01:54 · 7 answers · asked by Taryn 2 in Science & Mathematics ➔ Biology
Krebs cycle is a part of aerobic respiration.
Glucose(by glycolisis) ----------------->Pyruvate(by krebs cycle O2) + 2ATP energy-------------------->CO2 + H2O +energy (36 ATP)
total energy =38 ATP
While glycolisis takes place in the cytoplasm,krebs cycle takes place in mitochondria.
2006-09-26 03:39:18 · answer #1 · answered by live_let.live 3 · 0⤊ 0⤋
Krebs cycle occurs when cells respires in present of oxygen. This take place in the mitochondria.
Glucose-glucose 6 phosphate - fructose 6 phosphate- fructose 1,6 bisphosphate- glyceraldhyde 3 phosphate ... - pyruvate.
Pyruvate is then enter the krebs cycle to generate energy (ATPs)
one mole of glucose give about 36 moles of ATPs.
2006-09-25 20:35:12 · answer #2 · answered by YY 1 · 0⤊ 0⤋
http://www.uic.edu/classes/bios/bios100/summer2002/lect10.htm
This site explains the Krebs Cycyle and Glycolysis in mostly plain terms.
2006-09-25 17:09:03 · answer #3 · answered by jediaaylas 2 · 1⤊ 0⤋
From Wikipedia:
Krebs cycle is a series of chemical reactions of central importance in all living cells that utilize oxygen as part of cellular respiration.
2006-09-25 17:06:51 · answer #4 · answered by Shaun 4 · 0⤊ 0⤋
AKA citric acid cycle. occurs in the mitochondria, more specifically the matrix of the mitochondria. the cycle begins with pyruvic acid (created from glycolysis) and produces NADH, FADH, ATP, and CO2 (a byproduct).
2006-09-25 17:24:37 · answer #5 · answered by rachel k 4 · 0⤊ 0⤋
Simply put, it is the serial (in several steps) degradation (decomposition) of a sugar molecule; this process will have the result of generating energy necessary for the normal functioning of the cells.
2006-09-25 17:10:55 · answer #6 · answered by Yacine B 3 · 0⤊ 0⤋
go to this site.
http://wine1.sb.fsu.edu/krebs/krebs.htm
wish i have helped you in some ways
2006-09-25 17:16:30 · answer #7 · answered by nicel 2 · 0⤊ 0⤋