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what is x? thanks

2006-09-25 16:55:42 · 9 answers · asked by Anonymous in Education & Reference Homework Help

9 answers

use half formula

-3+sqrt(7)
-3-sqrt(7)

2006-09-25 17:01:43 · answer #1 · answered by iyiogrenci 6 · 0 0

The answer is indeed -3 +/- square root of 7. If you don't want to use the quadratic equation, you can use the complete the square method.

x^2 +6x + 2 = 0

You want to add a number to both sides of the equation that will enable you to have two equal factors on the right side of the equation. In this case the number is 7. (To find the number take the middle term, in this case 6, divide it in half and square it. 6/2=3 and 3^2=9. You already have 2 on the right side of the equation, so you want to add 7 to make 9).

x^2+6x+2+7= 7

X^2+6x+9= 7

(x+3)(x+3)=7

Now we take the square root of both sides. So

(x+3)= square root of 7

Therefore, x= -3 + the square root of 7. It's conjugate, -3 - the square root of 7 is a solution as well.

2006-09-26 15:13:59 · answer #2 · answered by Anonymous · 0 0

This is a quadratic equation in the form ax^2+bx+c=0, where a=1, b=6, and c=0. The solution is obtained using the quadratic formula:

x= [-b +/-sqrt(b^2 - 4*a*c)]/2a

2006-09-26 00:02:45 · answer #3 · answered by gp4rts 7 · 0 0

If you were given this equation, you already have some familiarity with the quadratic formula. Someone has already given it to you and you need to work it to develop competence, not just asking what x is.

2006-09-26 00:10:00 · answer #4 · answered by Anonymous · 0 0

Wow...this is deep. I guess I should've sat in the front of the class and paid attention.

2006-09-26 00:04:27 · answer #5 · answered by Anonymous · 0 0

x = -3 - root(7)

or

x = root(7) - 3

2006-09-26 00:09:27 · answer #6 · answered by Nighteyes 3 · 0 0

use quadratic formula...it works every time

2006-09-26 00:08:46 · answer #7 · answered by ashley 3 · 0 0

+/- 0.355......plus or minus 0.355/ u have to use the quadratic formula... positive!

2006-09-26 00:02:04 · answer #8 · answered by Anonymous · 0 0

I could do it but what would that teach you?

2006-09-26 00:04:46 · answer #9 · answered by CallMeDigitalBob 3 · 0 0

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