% = (mass of part g)/(mass of whole g) X 100 by using that formula, try to solve for the percentage of mixture

Question

Mixture of salt = 1.2, iron = 0.85

cup/mix = 18.2
cup = 1.68
mix = 16.52

beaker/salt = 31.94
beaker = 30.74
salt = 1.2

filter paper/sand =
filter paper = 1.22
sand =

Wax paper/Fe (iron) = 1.17
Wax Paper = 0.32
Fe = 0.85

Answer 1

You have given the formula--just apply it. salt = 1.2g, iron = 0.85g; whole = 1.2g+0.85g = 2.05g. % salt = (1.2g/2.05g)*100, % iron = (0.85g/2.05g)*100

Same with all the others, except you have already been given the whole.

Answer 2

1.2/16.52x100=% salt
.85/16.52x100=% Fe
1.2+.85=2.05
16.52-2.05=mass of sand=14.47
14.47/16.52x100=% sand