if a rocket initially at rest accelerates at a rate of 50m/s^2 for one minute, its speed will be?

Answer 1

Known values are as follows:

vi= 0 m/s
a= 50 m/s^2
t= 60 s

Use the equation vf=vi + at ....... Good Luck!

Answer 2

use the equation :
v = u + a * t;
where V is velocity or the speed you want to find, u is the initial speed which is zero in this case; a = acceleration which is 50 m/s^2 and t is time which is 60 seconds in this case.

therefore,

v = u + a * t
= 0 + 50m/s^2 * 60 s

= 3000 m/s

speed is same as velocity with meters/second as units.
Hope that helps!

Answer 3

The equation for velocity given the acceleation is

v = a * t so t in seconds is 60 and then

v = 50 * 60 = 3000 m/sec.

Answer 4

v = at is the formula you're looking for. v = speed a = acceleration t = time v = at v = (50 m/s²) (60 s) v = 3000 m/s you could verify you're using the incredible formula by searching on the instruments contained in the second one step of the equation. once you multiply m/s² and s 2 of the s's will cancel and also you're left with merely m/s (the instruments for speed).

Answer 5

if i understand it your equation states it travels 50 meters per second squared so the answer is 50m/60^2
since there are 60 seconds in one minute substitute 60 for the s if the s means seconds

Answer 6

Take a look at the units. You want to have m/s at the end. So multiply [m/s^2]*[s] and you get [m/s] exactly what you want. So (50m/s^2)*(60s)=3000m/s

Answer 7

here i think you directly can't apply equations of motion.
because the acceleration due to gravity changes with change in altitude.

so the method involves integration...
if you are assuming that acceleration due to gravity doesn't change then the method given by others is correct and you can simply apply newton's equation of UNIFORM motion

Answer 8

wouldnt it be 600m/s....not sure though.. so dont quote me

Answer 9

300m/s

Answer 10

it will be at 150000 m/s