At the surface of the ocean, the water pressure is the same as the air pressure above the water, about 15 lb/in^2, Below the surface the water pressure increases by about 3.64 lb/in^2 for every 10 ft of descent.
Write a function which expresses the water pressure in pounds per square inch as a function of the depth in inches below the ocean surface
f(x) = 15+3.64x/120
At what depth is the pressure 100lb/in^2 Include the units in your answer
2006-09-25 16:20:12 · 3 answers · asked by AC 1 in Science & Mathematics ➔ Mathematics
100=15+3.64*X/120
X=???
Solve for x and that is the answer in inches
2006-09-25 16:29:49 · answer #1 · answered by anonomous 3 · 0⤊ 0⤋
You already have the equation. Put 100 on the left side and solve it for x, which will be in inches since you set up the equation that way.
My only correction to your formula is that sea water pressure is actually about 3.70 psi per 10 ft. (64 lb per cu ft over 144 x 10 over12)
2006-09-25 23:33:55 · answer #2 · answered by Steve 7 · 1⤊ 0⤋
f(x) = 15 lb/in^2 + 3.64x/120 lb/In^2
100 lb/in^2 = 15 + 3.64x/120
multiply both sided by 120
12000 = 180 + 3.64x
move constants to 1 side
3.64x = 11820
x = 3247.25 inches
2006-09-25 23:30:26 · answer #3 · answered by want2no 5 · 0⤊ 0⤋