what is the integral of sec^2x/1-tanx dx?

4 ⤊

2006-09-25 16:14:33 · 4 answers · asked by BMac 3 in Science & Mathematics ➔ Mathematics

yes, (secx)^2

2006-09-25 16:21:22 · update #1

Make the substitution u = tan x, du = sec^2x dx
Then integrate du/(1-u) = -ln(1-u)+ C = -ln(1 - tan x) + C

2006-09-25 16:22:28 · answer #1 · answered by steiner1745 7 · 1⤊ 0⤋

This is a simple u substitution, let u = tan x, so du = sec^2x. it becomes -ln(1-tanx)+C

2006-09-25 23:16:22 · answer #2 · answered by need help! 3 · 3⤊ 0⤋

Do you mean (sec x)^2/(1-tan x)?

2006-09-25 23:19:02 · answer #3 · answered by Isaac 2 · 0⤊ 0⤋

-ln(1-tanx)+C

2006-09-25 23:25:24 · answer #4 · answered by johnny 1 · 0⤊ 0⤋