an orbiting satellite...?

Question

here's the case...

A satellite is orbiting at 3600 km above the earth surface. If the earth's radius is 6400 km, and the satellite is orbiting with a constant velocity, find its velocity in km/s!

complete with the step and theoritical explanation pliz!!! *YAY thanks a lot!!!!

Answer 1

I am guessing you would mean a geo-stationary satellite or one that remains over the same point of the earth at all times. This will establish the satellite's orbital period, something not mentioned in the problem.
So, according to your problem the earth's radius is 6400Km. What you are looking for is the circumference not of the earth, but of the "circle" created by the satellite's path around the earth. Add the altitude, or 3600Km, of the satellite to the radius of the earth, 6400Km. 6400 + 3600 = 10,000Km
10,000 as the new radius, use that to figure out the circumference. The equation for a circle's circumference is 2*"pi"*r OR 2 multiplied by pi multiplied by radius.
To keep the number of digits the same, use the approx value for pi of 3.1416 [Side note: pi is a non-repeating, non-terminating decimal meaning it goes on forever as far as anyone knows.]
Take 2 multiplied by 3.1416 multiplied by 10000 which gives 62,832Km.
Now, the equation for speed is:
speed = distance / time OR s=d/t
s=62,832Km/24hours
s = 2,618 kilometers per hour. There are 3600 seconds in one hour [60 minutes times 60 seconds equals 3600 seconds in all], so last step is to convert to seconds by 2618/3600 which gives:
0.7272Km/s

Now, if you do not mean a geo-stationary satellite, the velocity could be anything as long as it orbits.

Answer 2

To tired to do this, but thanks for the two points