why is it necessary to use deuterated substances in 1H NMR?

Question

I need to reasons please someone help me

Please i need one more someone please give me one more please

Answer 1

If your solvent was not deuterated in proton NMR, then the solvent proton signals would overpower all other peaks and you would not see the sample at any useful level of resolution.

Answer 2

If you used entirely protonated species as the solvent in 1H NMR, the solvent would saturate the system.

Deuterated solvents actually have a slight impurity of the mono-protonated solvent (e.g. if you're using d6-benzene, there's a small amount of C6D5H present). The signal you see that you attribute to the solvent peak (if you don't use TMS to set a 0, you can reference the solvent peak at whatever its normal shift is to figure out the positions of the other peaks) is actually that trace of the monoprotonated solvent. Purely deuterated solvents would not show up in 1H NMR. That trace is low enough that the compound of interest would not get swamped out by the solvent.

Answer 3

Well, never did NMR, but with GC/MS the deuterated ion is necessary to differentiate your standard you add to the mix, from the compounds that naturally exist in nature, and may be part of your sample.