5z+7=6(z-2)-4(2z-3)?

First thing you do is mulitply the number on the outside of the brackets by each of the number inside the brackets.

5z + 7 = (6z - 12) - (8z - 12)

Now, you want to remove the brackets, but make sure you reverse the sign if there is a - infront (it's like multiplying again by an imaginary -1)

5z + 7 = 6z - 12 - 8z + 12

Move the numbers containing "z" to one side and constants to the other. Remember to switch signs when you move across the "=" sign.

5z - 6z + 8z = -12 +12 -7

Add the like terms together.

7z = -7

Isolate the "z" by dividing both sides of the equation by number in front of "z".

7z/7 = -7/7

7 divided by 7 = 1 and -7 divided by 7 = -1

So the final answer is:

z = -1

Double check your answer by plugging the -1 into all the "z" variable.

5(-1) + 7 = 6[(-1) - 2] - 4[2(-1) - 3]
-5 + 7 = -6 - 12 - 4(-2 - 3)
2 = -6 - 12 + 8 + 12
2 = 2

If both sides equal, then the answer is correct.

2006-09-25 15:47:42 · answer #1 · answered by Kelvin C 2 · 0⤊ 0⤋

Solve Z on one side of the equation and the values on the other.

5z + 7 = 6 (z-2) - 4(2z -3)
Multiply 6 and 4 through their respective parenthesis, and don't forget the NEGATIVE on the 4 goes through also:
5z +7 = (6z - 12) + (-8z +12)
5z +7 = 6z - 12 - 8z +12
Move the z to one side of the equal sign (add the opposite)
5z - 6z +8z + 7 = -12 +12
Get the 7 on the opposite side
5z - 6z +8z = -12 +12 -7
7z = -7
z = -1

2006-09-25 15:35:50 · answer #2 · answered by captn_carrot 5 · 0⤊ 0⤋

5z+7=6z-12-8z+12
5z+7= -2z
-5z-2z=7
-7z=7
z= -1
Hope this helps. Not sure if your trying to solve for z.

2006-09-25 15:49:57 · answer #3 · answered by lewy_413 1 · 0⤊ 0⤋

5z+7=6z-12-8z+12
5z+7=-2z
7z+7=0
z=-1

C'mon dude, its simple. Do the same thing on the left of the equation as the right and you will always solve the variable!

2006-09-25 15:45:08 · answer #4 · answered by Rckets 7 · 0⤊ 0⤋

5z+7=6(z-2)-4(2z-3)
5z+7=6z-12-8z+12
and that is as far as I am going to go...good luck buddy...

2006-09-25 15:43:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋

5z + 7 = 6z -12 -8z +12
5z + 7 = -2z
7 = -7z
-1 = z

2006-09-25 15:37:09 · answer #6 · answered by John 2 · 0⤊ 0⤋

5z+7=6z-12-8z+12
5z+7= -2z
7z=-7
z= -1

2006-09-25 15:37:11 · answer #7 · answered by starrchick101 3 · 0⤊ 0⤋

3(z+2)=5z+6 then the quantity outdoors the paranthesis ability you will multiply it those witnin the paranthesis. 3z+6=5z+6 then you somewhat will circulate the comparable form of numbers comparable ingredient.. 6-6=5z-3z 0=2z then z=0/2 meaning z=0

2016-12-12 15:10:48 · answer #8 · answered by spadafora 4 · 0⤊ 0⤋

5z+7=6(z-2)-4(2z-3)
5z+7=6z-12-8z-12
5z+7=-2z
7=-2z-5z
7=-7z
z=-1

2006-09-25 15:38:04 · answer #9 · answered by Anonymous · 0⤊ 0⤋

5z+7=6(z-2)-4(2z-3)
5z+7=6z-12-8z+12
5z-6z+8z=7-12+12
-7z=7
z=-7/7
z=-1

2006-09-25 15:38:53 · answer #10 · answered by Help me 3 · 0⤊ 0⤋

5z+7=6(z-2)-4(2z-3)?

20 answers