Please help with my math problem.?

Question

At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart?

Answer 1

4:20pm

Answer 2

Rate times time equals distance.

Let t be the time the first car travels. The second car will travel t-1. The distance the first car travels will be 55t. The second car will go 60(t-1). You want the total distance to be 285 miles, so

55t + 60(t - 1) = 285

55t + 60t - 60 = 285

115t = 345

t = 345/115 = 3

So the first car travels 3 hours, the second travels two hours, and the time you're looking for is 4:00 pm. (Assuming no time zone changes.)

Answer 3

4:00 is correct, 1st car leaves, goes 55 miles, gets there at 2, from 2-3 each car goes another 55+60 miles = 170, from 3-4 they go another 55+60 = 285 total and the time is 4:00.

Answer 4

At 4 pm the vehicles will be 285 miles apart

after 1 hour vehicle 1 is 55 miles

after hour 2 vehicle 1 is at 110 miles
and vehiicle 2 is at 60 miles or total distance 170 miles

at hour 3 vehicle 1 is at 165 miles
and vehicle 2 is at 120 miles or total distance 285 miles

Answer 5

around 3:00 and 4:00

Answer 6

4 pm

Answer 7

4:00 p.m.

Answer 8

The car is speeding in a small town, sounds like to me. Better fire the drier and get a bus!!

Answer 9

4:00pm

1st hour- 55miles
2nd hour-170miles
3rd hour-285miles

Answer 10

3:00 pm
Not too tricky...