Ok here is the problem:
The measure of the supplement of an angle exceeds twice the measure of the complement of the angle by 20. Find the measure of half of the complement.
Can someone please help me....I am having trouble figuring out the starting equation.........thanks in advance!!!!!!!!!!!!!
2006-09-25 15:02:24 · 6 answers · asked by Jen 2 in Education & Reference ➔ Homework Help
Call A the measure of the angle (in degrees)
Its supplement is 180 - A.
Its complement is 90 - A.
Now put the statements into equation form:
180-A = 2(90-A) + 20
Solve for A.
2006-09-25 15:06:53 · answer #1 · answered by just♪wondering 7 · 0⤊ 0⤋
It could be anything. If you use the supplement as 90° then half the complement would be 35°. Is there anymore information? If so, email me, and I could help you. I'm already tutoring someone in geometry and I have geometry as my class, so I'd be of much help. Email me if you like.
2006-09-25 15:05:59 · answer #2 · answered by ViCKi!™|` 5 · 0⤊ 1⤋
SA=2CA+20
2006-09-25 15:06:49 · answer #3 · answered by bbw 2 · 0⤊ 0⤋
I remember that there is a thorem that if the two sides of a traingle are equal then the angle opposite to them are also same. Please see the thorem. So the bisectors make a isoscele traingle with the side in between the angles were getting bisected.I will later write you the proof of the theorm. As the each half of the angles are equal, then the full angles are equal. here you found the two angles are equal. As per definition: in a traingle if the two angles are equal, then that traingle is called a isoscele traingle.
2016-03-27 09:45:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋
180 - x = 2(90 - x) +20
You need to find (90 - x)/2 after you find x! This was a nice, tricky question! Good luck! You'll get it now
2006-09-25 15:05:38 · answer #5 · answered by J G 4 · 0⤊ 0⤋
2x+x+20=0 i think thats it.
2006-09-25 15:04:47 · answer #6 · answered by Patricio B 6 · 0⤊ 1⤋