The question is:
"To raise the temperature of a mass of water from 25.0 degrees C tp 50.0 degrees C requires 7.5 kcal. Calculate the mass of water in grams. (specifric heat of water= 1.0 cal/ (g) (degrees C)
The formula I got was
Q/ ΔT x C=M
However, the answer is incorrect. Can someone please explain and demonstrate how to solve this problem?
Thanks in advance.
2006-09-25 13:50:29 · 2 answers · asked by mbtafan 3 in Science & Mathematics ➔ Chemistry
the formula is q = mct(delta)
where "q" iz the amount of energy in kilojoules, m is the mass of the water in litres, not mililitres. c is the constant and delta t is the change of temperature in degrees celsius.
then u just plug ur info into the equation.
7.5 = m(1.0)(25)
7.5 = 25m
m = 0.3 Kg or 300 g.
hope this helps u out!
2006-09-25 14:04:42 · answer #1 · answered by mattcam89 2 · 0⤊ 0⤋
Your formula is incorrect. The basic equation is
Q=m*c*deltaT, so m =Q/(detlaT*c). The c is in the denominator.
See http://en.wikipedia.org/wiki/Specific_heat
2006-09-25 13:57:13 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋