the sqare of a number is 56 more than the number itself?

Question

i need help with this problem. please explain how you would get the answer, you dont need to give me the answer, just show me how to get the answer. thank you.

Answer 1

Start by expressing the problem as an equation:

x^2=x+56
subtract x and subtract 56 from both sides
x^2-x-56=0
Now solve for the roots using the quadratic equation:

(-b+/-Sqrt(b^2-4ac))/2a


a=1
b=-1
c=-56

x=8 or -7

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Answer 2

0 is the different. somewhat algebra will instruct us: enable x² = x Then x² - x = 0 component and procure: x(x - a million) = 0 Then both x = 0 or x - a million = 0 So x = 0 or x = a million i imagine 1 million is only the only variety which has a sq. root of itself.. sq. root of four is two sq. root of 9 is 3 sq. root of 16 is 4 sq. root of 25 is 5.. So on and so on. 0 or a million