Either set x = 0 and solve for y, or put the equations in slope-intercept form (y = mx + b)... then just read off 'b'.
1) 2/3x + y/3 = -1/3
Subtract 2/3x from both sides:
y/3 = -2/3x -1/3
Multiply by 3:
y = -2x -1
So the y-intercept (b) is 1.
Try the rest on your own...
2006-09-25 13:21:06
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answer #1
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answered by Puzzling 7
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When X = 0.
Just plug 0 into the equation when you see an X.
2/3 * X + Y / 3 = -1 / 3
2/3 * 0 + Y / 3 = -1 / 3
0 + Y / 3 = -1 / 3
Y = -1
The Y intercept is -1
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3/5 * Y - X / 5 = 6 / 5
3/5 * Y - 0/5 = 6/5
3/5 * Y - 0 = 6/5
3Y = 6
Y = 2
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4/5 = -1/3 * X - 3/4 ??? Where's the Y?? I think you typed this one incorrectly. You can't have a Y intercept without Y.
2006-09-25 20:19:03
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answer #2
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answered by nondescript 7
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the y intercept is the point on the graph where x=0
2/3X+Y/3=-1/3 if x were 0,
2/3*0+y/3 = -1/3
y/3=-1/3
y=1, x=0
the last one has a typo. the equation should be in terms of x and y, you only have x
2006-09-25 20:23:25
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answer #3
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answered by DanE 7
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1.y/3+2/3x=-1/3
multiplying by 3
y=-2x-1
y intercept -1
2. multiplying by 5
3y-x=-6
3y=x-6
y=x/3-2
y intercept=-2
3.multiply by 60
48=-20x-45
20x=-93
line parallel to y axis
so no intercept
2006-09-25 20:34:00
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answer #4
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answered by raj 7
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#1 it would be -1
Y= -2X-1
#2 it would be -2
Y=1/3X-2
and there is no Y in the last one
sry
2006-09-25 20:21:32
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answer #5
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answered by musicalkoreangirl 3
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(i) y-int = -1/3
(ii) y-int = -2
(iii) No y-int because the line is verticle and parallel to the y-axis.
All the BEST !
2006-09-25 20:25:59
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answer #6
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answered by srjione 3
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The first would be the +Y/3
The second would be the -X/5
The last would be the -3/4
2006-09-25 20:20:21
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answer #7
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answered by Anonymous
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1, 2, there is no Y in the third problem you 'tard
2006-09-25 20:21:15
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answer #8
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answered by JonFugeEverybody! 2
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this is not a very efficient way to do your homework.
2006-09-25 20:20:18
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answer #9
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answered by Tom S 3
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