What mass of P4 is required to react with excess oxygen and produce 11.121 g of H3PO4, if the percent yield is

69 ⤊

What mass of P4 is required to react with excess oxygen and produce 11.121 g of H3PO4, if the percent yield is

66.638%?
P4 + 5O2 + 6H2O ----> 4H3 PO4

2006-09-25 13:02:32 · 1 answers · asked by ballinkickz 1 in Science & Mathematics ➔ Chemistry

1 answers

From the formula for Phosphoric acid, the FW = 98.00 g/mole.

11.121 g / 98.00 g/mole = 0.1135 moles produced.

from the equation: one phosphorus atom yields one phosphoric acid:

0.1135 moles / 0.66638 = 0.1703 moles of phosphorus needed.

0.1703 moles * 30.97 g/mole = 5.2742 grams of Phosphorus.

2006-09-26 01:17:14 · answer #1 · answered by Richard 7 · 69⤊ 0⤋