-a^2b-a if a=-1/2 and b=1/4?

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-a^2b-a if a=-1/2 and b=1/4?

(Please show your work. Thank you!)

2006-09-25 12:45:03 · 3 answers · asked by Chelsey 5 in Education & Reference ➔ Homework Help

3 answers

-(-1/2)^2(1/4--1/2)
1/2(1/2)=1/4
1/4(1/4+2/4)
1/4(3/4)
3/16 I hope that's right

2006-09-25 12:48:19 · answer #1 · answered by Amber 3 · 0⤊ 0⤋

Amber put
-(-1/2)^2(1/4--1/2)

but you had written
-a^2b-a

So I think it is
-(-1/2)^2(1/4)--1/2

Then solving:
= -(1/4)(1/4)+1/2
= -1/16+1/2
= -1/16+8/16
= 7/16

2006-09-25 21:46:07 · answer #2 · answered by Robert B 5 · 0⤊ 0⤋

-.5^2(.25)-.5
-.25(.25)-.5
.06-.5
-.44 (i think)

2006-09-25 19:49:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋