What is the answer to [f(2)-f(1)]-[f(1)-f(0)] ?

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What is the answer to [f(2)-f(1)]-[f(1)-f(0)] ?

2006-09-25 12:11:33 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

sorry. It says "Consider the function f(s)=s(to the power of 2)-6s+9

2006-09-25 12:29:01 · update #1

3 answers

f(s) = s^2 -6s + 9 , so f(s) = (s-3) ^2

f(2) = (-1)^2, getting f(2)=1

f(1) = (-2)^2 , f(1) = 4

f(0) = (-3)^2, f(0) = 9

you wanna kno

f(2)-f(1)-f(1)+f(0)= 1 -4 -4 +9

so we get '2'.

2006-09-25 16:10:40 · answer #1 · answered by free aung san su kyi forthwith 2 · 0⤊ 0⤋

[f(2) - f(1)] - [f(1) - f(0)] =

f(2) - f(1) - f(1) + f(0) =

f(2) - 2f(1) + f(0)

2006-09-25 19:27:05 · answer #2 · answered by Dimos F 4 · 0⤊ 0⤋

Depends on how you define f(x)

2006-09-25 19:20:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋