Help?
2006-09-25 11:51:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2 = log7(49)
log7(5x-1) = log7(49*(x-2))
5x-1 = 49(x-2)
5x-1 = 49x-98
97 = 44x
x = 97/44
IIRC.
2006-09-25 12:01:11 · answer #1 · answered by CaptainObvious 3 · 2⤊ 0⤋
log(7)(5x - 1) = 2 + log(7)(x - 2)
log(7)(5x - 1) - log(7)(x - 2) = 2
log(7)((5x - 1)/(x - 2)) = 2
this can be rewritten as
7^2 = (5x - 1)/(x - 2)
49 = (5x - 1)/(x - 2)
49(x - 2) = 5x - 1
49x - 98 = 5x - 1
44x = 97
x = (97/44)
If you go to www.quickmath.com and type in
(log(5x - 1))/(log(7)) = 2 + ((log(x - 2))/(log(7)))
so that it will be able to work it, it will give you the same answer.
2006-09-26 00:25:30 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
log7(5x-1)=log7(49)+log7(x-2)
(5x-1)=49(x-2)
2006-09-25 19:09:20 · answer #3 · answered by need help! 3 · 0⤊ 0⤋
the answer of 3
2006-09-25 18:53:00 · answer #4 · answered by San Fran Kid 2 · 0⤊ 0⤋
ask the teacher
2006-09-25 18:53:20 · answer #5 · answered by [brown♥eyed♥girl] 4 · 0⤊ 0⤋