help with this problem???

Question

list all of three- digit numbers that have all of the following characteristics:

~ it's a multiple of 3
~it is an odd number
~it is less than 132
~it's greater than 117...

explain excatly how you solved this problem. show all your work..?? please if you know....please help me..

Answer 1

when you add up the digits of multiples of 3 the sum will be divisible by 3
117,123,129

Answer 2

O.K., you know that there have to be a limited number of correct responses for this problem because the parameters being set are given as odd numbers between 117 and 132. So, because it has to be odd numbers, guess what?

117 works, it is divisible by 3 and it is an odd number.(117 divided by 3 = 39. However, one of the conditions is that our answers be greater than 117, therefore rule 117 out. But here's the beauty of using 117 as a starting point. Start adding 3's and the next number you come up with is 120. However 120 is an even number, so go to the next, or 123. It works.

Just keep going from here. 126 is out because it is even, hence, go to 129. It works! Now, you can't go any further because 129 + 3 = 132, and we already know that our solutions have to be less than 132.

Therefore, our final solution set is going to look like this: {123, 129} You can test these out by dividing each number in the solution set by 3. 123 divided by 3 = 41. 129 divided by 3 = 43.

Answer 3

Hi. I love this problem because you get to use a little trick I picked up a long time ago.
Here's the trick first: when you add the individual numbers in any number together, you'll be able to tell if the number is a multiple of three or not.
Example: 121 = 1+2+1=4 NO
324 = 3+2+4=9 YES
So, to answer your question, all I did was get a little piece of scrap paper, wrote down all the numbers between 117 and 132, scratched all the even numbers, and added the rest like I showed you. Try it, and see if you get 123 and 129.
Good Luck! Hope it helped you.

Answer 4

A key to answering this question is knowing how to find if a number is a multiple of three. The trick is to add all digits, and if the sum is a multiple of three, then the original number is, as well. Example: 162 is a multiple of three because 1+6+2=9. 9 is a multiple of three, so 162 is, as well.

Now, just go through the odd numbers between 117 and 132 to find your answers.
119: 1+1+9=11---no
121: 1+2+1=4--no
123: 1+2+3=6--Yes!
125: 1+2+5=8--no
127: 1+2+7=10--no
129:1+2+9=12--Yes!
131:1+3+1=5--no.

Answer 5

123,129
to get the wanted numbers u add the digits of the three-digit numbers if their sum is divided by three it will be right

Answer 6

"explain excatly how you solved this problem. show all your work..?? "

sounds like you are trying to get others to do your homework for you. TSK TSK TSK. It shouldn't be that difficult if you apply yourself.

Answer 7

123
129
hope this helps