rank the following compounds from (1) lowest to (4) highest boiling points.
butane
2,3-dimethylbutane
hexane
2-methylpentane
thanks so much.
2006-09-25 10:02:42 · 5 answers · asked by keanweaner 4 in Science & Mathematics ➔ Chemistry
please explain, as i am very new to this.
2006-09-25 10:07:05 · update #1
Butane (I will assume n-butane): bp = -0.5°C
2,3-dimethylbutane: bp = 57.9°C
2-methylpentane: bp = 60.2°C
Hexane (I will assume n-hexane): bp = 68.7°C
2006-09-25 10:08:04 · answer #1 · answered by Dave_Stark 7 · 1⤊ 4⤋
typically the smaller the molecule or lower molecular weight the lower the boiling point, but i would look some of those up. but if i had to guess i would pick butane, 2- methylpentane, hexane, the 2,3-dimethylbutane
2006-09-25 17:47:27 · answer #2 · answered by n_hall_22 3 · 0⤊ 0⤋
generally, the more that is in the compound the lower the boiling point
2006-09-25 17:05:25 · answer #3 · answered by allusional 2 · 0⤊ 0⤋
butane bp = -0.45 degrees C
2,3-dimethylbutane bp = 57 to 59 degrees C
2-methylpentane bp = 60 degrees C
hexane bp = 69 degrees C
2006-09-25 17:07:51 · answer #4 · answered by Richard 7 · 5⤊ 0⤋
The more carbons and other groups attached, the HIGHER the boiling point will be.
2006-09-25 17:11:53 · answer #5 · answered by Zelda Hunter 7 · 0⤊ 0⤋