A certain metal, M forms two oxides M3O and M2O.
If the percent by mass of M in M3O is 61.0 % what is the percent by mass of M in M2O ?
2006-09-25 08:39:26 · 3 answers · asked by BUM 1 in Education & Reference ➔ Homework Help
M3O has 61% M, thus it has 39% Oxygen. Oxygen's mass is 16, so the total mass is 16 / 39% = 41.0.
3 * M therefore equals 41 (total) - 16 (oxygen) = 25, so M = 8.3333.
To find the percentage in M2O: 8.33333 * 2 + 16 = 32.666667. 16.666667 / 32.666667 = 51.0% M in M2O.
2006-09-25 08:46:50 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
100%-61%=39% which is the percentage of O which is oxygen which has an atomic mass of 16.
.39x=16 to find the total mass of the molecule.
x=41.0256
41.0256-16=25.0256 which is the weigth of M3
25.0256/3=8.341866 = the atomic weight of M
M2 therefor is 8.341866 * 2 = 16.6837
16.6837 + 16 = M2O = 32.6837
to find the percentage of M in M2O is 16.6837/32.6837
which gives you 51.046 %
2006-09-25 08:56:23 · answer #2 · answered by atothek96 2 · 0⤊ 0⤋
enable ethanol be noted as E. enable the ethanol answer in water be noted as S. The molecular weight of ethanol, C2H6O, is 40 six. 2.76molE/1000mLS x 46gE/1molE x 1mLS/0.978gS = 0.130gE/1gS which means 13.0g ethanol/100g answer, so the respond's 13.0 wt/wt% ethanol to 3 significant figures.
2016-12-12 14:56:55 · answer #3 · answered by donenfeld 4 · 0⤊ 0⤋