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y - 5 /3 =2

2006-09-25 07:39:57 · 11 answers · asked by fallenangel4504 2 in Education & Reference Homework Help

Please explain how to do it!

2006-09-25 07:40:26 · update #1

11 answers

I'll assume you mean: (y-5) / 3 = 2
Step 1: Multiply both sides by 3.
(y-5) / 3 = 2
3* (y-5) / 3 = 2 * 3
(y-5) = 6

Step 2: Add 5 to both sides:
y - 5 + 5 = 6 + 5
y = 11

If you meant y - (5/3) = 2, then add 5/3 to both sides:
y - (5/3) + (5/3) = 2 + (5/3)
y = 2 + 5/3
y = 3 + 2/3

2006-09-25 07:43:16 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

Y-5/3=2
Y =2+5/3
Y =11/3
so Y =three and two thirds[3 2/3]

2006-09-25 14:58:57 · answer #2 · answered by pasky 2 · 0 0

y-5/3=2
add 5/3 to both sides
y=2+5/3=6/3+5/3 2 is 6/3 multiply 2 by 3 put over 3
y=11/3=3 2/3 divide 11 by 3 gives 3 with 2 remainder
2 remainder is 2/3

2006-09-25 14:52:48 · answer #3 · answered by Anonymous · 0 0

y-5/3 =2
and "5/3" to both sides
y-5/3 +5/3 = 2 +5/3
(if you add the same number to each side of an equation, then the answer remains the same)

this leaves you with y= 2 & 5/3
Since 5/3 +1 and 2/3, y =3 1/3

2006-09-25 14:50:21 · answer #4 · answered by Anonymous · 0 0

y-5/3=2
+5/3 +5/3
y=2

2006-09-25 14:48:46 · answer #5 · answered by zamora 1 · 0 0

add 5/3 to the other side of the problem. convert 5/3 to a decimal then add the 2 plus the decimal y=3.666

y=2+5/3

2006-09-25 14:45:17 · answer #6 · answered by Bioman2005 2 · 0 0

it's a matter of moving the numbers from one side of the equation to the other by doing the opposite mathmatical sign (plus or minus, divide or multiply, etc) to get Y to stand alone...

y-5/3=2

y-5=2*3 or y-5=6

y=6+5 or y=11

2006-09-25 14:47:35 · answer #7 · answered by Jamie S 1 · 0 0

get the variable by itself. (add 5/3 to both sides)
now you have y=2+5/3
add 2+5/3 together
there's your answer!























(y=11/3)

2006-09-25 14:43:44 · answer #8 · answered by synchsk8demon 2 · 0 0

(y-5)/3 = 2
multiply both sides by 3

y-5 = 6
add 5 to both sides

y=11

2006-09-25 14:43:43 · answer #9 · answered by t_e_sumner 3 · 0 0

Isolate the y on one side, but addin 5/3 to both. You should be able to take it from there??

2006-09-25 14:43:29 · answer #10 · answered by Anonymous · 0 0

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