The compound NH2OH is oxidised by Fe3+,which itself is reduced to Fe2+. In an experiment,2 mol of Fe3+ react exactly with 1 mol of NH2OH.Determine the change in oxidation state of nitrogen in NH2OH.
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2006-09-25 06:34:17 · 4 answers · asked by lemondevil88 2 in Science & Mathematics ➔ Chemistry
The oxidation state of nitrogen in NH2OH is -1. (Molecule is neutral, and none of the hydrogens are acting as hydrides, so each hydrogen is +1 and the oxygen is -2, so to balance all of the charge out, the oxidation state on the nitrogen must be -1.)
Since you are using two moles of iron (III) to oxidize one mole of hydroxylamine, the oxidation state is going from -1 to +1.
2006-09-25 07:21:06 · answer #1 · answered by TheOnlyBeldin 7 · 2⤊ 0⤋
kumo, wrote all of it out, consistent with danger i will assist simplify it conceptually Silver will grow to be oxidized (you would be able to desire to renowned this is going to grow to be +a million and that nitrate is -a million) now nitrogen 2 oxide means that nitrogen is +2, so oxygen is -2 (NO = independent, constantly account for quotes) now NO (+2 / -2) will grow to be NO3- (+5 / -6) you would be able to desire to renowned a thank you to stability for can charge, oxygen is amazingly plenty constantly -2, which may make nitrogen +5 (with a remander can charge of -a million) now stability, which kumo did for you 3Ag + NO3^- + 4H^+ ? 3Ag^+ + NO + 2H2O left section ( -a million + 4+ = +3) precise section (+3)
2016-12-18 16:43:07 · answer #2 · answered by dlabaj 4 · 0⤊ 0⤋
The iron is gaining a neg charge, since you have twice the amount of iron you have a gain of 2 neg charges for everyone 1 Nitrogen atom. This means that the nitrogen has to lose 2 neg charges, meaning it has been oxidized from +3 to +5.
2006-09-25 06:47:25 · answer #3 · answered by piercesk1 4 · 0⤊ 0⤋
go to wikipedia. that is where i start then i get links to other chem sites.
2006-09-25 06:36:42 · answer #4 · answered by devlin m 1 · 0⤊ 1⤋