I have problems with the homeworks mathematics. the question is this: Solve and check this problem: 8x-7(3-x) = 5(4+3x)-41?
2006-09-25 06:26:37 · 6 answers · asked by Dea Elmas@yahoo.com 1 in Science & Mathematics ➔ Mathematics
8x-21+7x=20+15x-41
15x-21=15x-21
0=0
So any real number will satisfy this equation
the answer is (-infinity,infinity)
2006-09-25 06:50:15 · answer #1 · answered by ioana v 3 · 0⤊ 1⤋
8x-21+7x = 20 +15x -41
15x -21 = 15x -21
15x-15x = -21+21
0=0
therefore, 8x-7(3-x) is equivalent to 5(4=3x)-41
2006-09-25 13:54:40 · answer #2 · answered by beagle52 2 · 0⤊ 1⤋
8x - 21 + 7x = 20 + 15x - 41
15x - 15x = 41 - 41
0 = 0
equation is 'satisfied' for any x e R, because whatever value you 'put' in x, 0 = 0, and that is also true.
2006-09-25 13:29:33 · answer #3 · answered by cybrdng 2 · 1⤊ 0⤋
the above equation is =
8x-21-7x= 20 + 15x - 41(just expand when removing brackets using the distributive law)
8x-7x-15x=20-41+21(put like terms together)
-14x= 0
x=o (thats the answer)
when u substitute 0 for x in the original equation you will see both sides are -21 so proving that x=0 is correct.
2006-09-25 13:33:33 · answer #4 · answered by cuervo 1 · 0⤊ 2⤋
No solution
The Numerical Coefficient and variables Cancell.
2006-09-25 14:17:56 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
stay awake in class and ya might just learn something instead ov haveing to rely on ppl
2006-09-25 13:34:36 · answer #6 · answered by nosferatu 1 · 0⤊ 1⤋