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this is regarding the experiment: composition of hydrates-- about the CuSO4 Pentahydrate, determing the percentage of water, the anhydrous salt...

2006-09-25 04:30:27 · 6 answers · asked by ethene 1 in Science & Mathematics Chemistry

6 answers

The anhydrous salt of cupric sulfate will take on its pentahydrate form in the presence of water. This causes the greenish white powder to turn bright blue. So if turns blue, there's water there.

2006-09-25 04:33:39 · answer #1 · answered by DavidK93 7 · 1 0

Anhydrous CuSO4 is white, while the hydarted is blue , and u can determine the water by wight difference.

2006-09-25 06:35:09 · answer #2 · answered by basimsaleh 4 · 0 1

Anhydrous copper (II) sulphate is a whitish-grey coloured powder, and in the presence of water, it becomes hydrated to give rise to hydrated copper (II) sulphate, which is blue in colour, thus resulting in a blue solution as it is also soluble in water.

2006-09-25 04:44:46 · answer #3 · answered by chemistry_freako 3 · 1 0

because when CUSO4 hydrates , changes color from with to blue.

2006-09-25 04:36:34 · answer #4 · answered by pregunton 2 · 1 0

Well, it'll colour blue when it's in a watery area...

2006-09-25 04:40:39 · answer #5 · answered by James N 1 · 1 0

honey, please read the text.
you are paying good money to go to school. at least someone is.

2006-09-25 05:26:54 · answer #6 · answered by WhoKnows?1995 4 · 0 1

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