Several answerers are getting confused by zeroth power and zeroth root. Anything to the zeroth *power* is 1, but anything to the zeroth *root* is undefined.
Here's one way to think of it:
We agree that x^0 = 1 (for any nonzero x). Therefore only 1 could possibly have a zeroth root. But, again, which x are we going to use? This means that the zeroth root of 1 is indeterminate. It would be written as 1^(1/0) but that is obviously undefined.
Another way to think of this is to think about the sequence of roots:
Cube root = x^(1/3)
Square root = x^(1/2)
"First" root = x^(1/1)
"Zeroth" root = x^(1/0)
So again, you can see that this would be undefined or indeterminate.
2006-09-25 04:22:55
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answer #1
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answered by Puzzling 7
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You want to solve X^0 = N for known N and unknown X.
X = 0 is no good. Substituting, we get 0^0 = N. 0^0 is undefined, but not completely undefined. It usually turns out to be either 1 or 0, depending on how you arrived at each zero. So if N = 1 or N = 0, then its zeroth root could be 0, but it might not be.
X = infinity is good. Substituting, we get infinity^0 = N. infinity^0 is completely undefined, so we have a perfectly good equation. The left-hand side can be anything, including N, even when N = 0 or N = 1.
2006-09-25 05:54:25
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answer #2
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answered by Anonymous
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if the number >1 then the zeroth root is infinity
if the number <1 then the zeroth root is 0
if the number =1 then it is undefined
2006-09-25 05:53:44
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answer #3
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answered by ioana v 3
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the zeroth root of 0 is 0 and for any other no is infinity
2014-12-25 06:17:46
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answer #4
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answered by Pulkit Gera 1
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1
2006-09-25 04:28:14
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answer #5
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answered by Karthik I 2
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zeroth root of any number is when >1 =infinity and when <1=0
when =1 is undefined
2006-09-25 04:29:34
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answer #6
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answered by Anonymous
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the zeroth root is DEFINED to be an identity operation
in the same way that X * 1 = X or
X + 0 = X
X ^ 0 = X
2006-09-25 04:33:02
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answer #7
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answered by michaell 6
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Undefined
2006-09-25 04:46:37
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answer #8
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answered by Lin 2
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Undefined. This comes from the definition of root.
2006-09-26 01:42:18
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answer #9
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answered by king64_shahab 2
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Infinity
2006-09-25 04:28:55
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answer #10
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answered by Anonymous
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