If a floor is 5 x 10, how long is it diagonal?

Question

If a floor is 5 x 10, how long is it diagonal to opposite corners?

Answer 1

Use Pythagorean Theorem:

5^2 + 10^2 = d^2
125 = d^2
square root of 125 is 5*square root of 5 , all together is about 11.18

Answer 2

DIAGONAL= 11.18UNIT

(Rectangle Side1=5 UNIT
Rectangle Side2=10 UNIT
DIAGONAL= 11.18UNIT)
(The Pythagorean Theorem (for either of the
triangles on opposite sides of the diagonal) says that a^2+b^2=c^2
(a^2 means a*a or a squared).
SO,5^2+10^2=diagonal ^2
25+100=diagonal ^2
diagonal ^2=125
diagonal=sqrt 125
diagonal=11.1803=11.18

Answer 3

What is the hypotenuse of a right triangle with legs 5 and 10?

Let x be the length of the diagonal.
Per Pythagoras: x^2 = 5^2 + 10^2
x^2 = 125
x = sqrt(125) = 5*sqrt(5) = 11.18.

Answer 4

A^2 + B^2 = C^2
ergo:
5^2 + 10^2 = C^2
25 + 100 = C^2
125^(1/2) = C which is approximately 1.18

Answer 5

make a right triangle
a^2 + b^2 = c^2
5^2 + 10^2 = c^2
25 + 100 = c^2
125 = c^2
c = (125)^.5 the sqr root of 125 .... a lil bigger than 11

Answer 6

.........5...........
......_____......
.....1....../1......
10 1..../..1......
.....1../....1......
.....1/......1.....
......--------......

The diagonal, width, and length would form a right triangle, thus you can use the Pythagorean theorem...

c^2=a^2+b^2

where:

c=the length of the hypotenuse
a=width
b=length

In this case we form a rigth triangle with the hypotenuse as the diagonal, the width with a value of 5 and the length with the value of 10...

Substitute the values and you will get the answer:

c^2=5^2+10^2
c^2=25+100
c^2=125
c=sqrt125
c=sqrt(5.5.5)

Answer:
c=5sqrt5

Answer 7

10'

Answer 8

you use, c²=a²+b² which c being the diagonal
so c²=5²+10²
c²=25+100
c²=125
c=11.18

Answer 9

11.18'
or 11' and 2 5/32"

Answer 10

5*sqrt 5