What year is MCMXXXI?

Question

its 19_ _

Answer 1

M = 1000
CM = 900
XXX = 30
I = 1

Total: 1931

Answer 2

Its quite simple.
Here's he conversion for Roman numerals:

M = 1000
D = 500
C = 100
L = 50
X = 10
V = 5
I = 1

Multiple symbols may be combined to produce numbers in between these values, subject to certain rules on repetition.

It is a rule place a smaller symbol before a larger value, so that, for example, one may write IV or iv for four. This will make the notation shorter because instead of writing IIII, you'd write IV

Always remember to read from left to right,

SO, back to your question:

MCMXXXI

M = 1000
C = 100
M = 1000
X = 10
I = 1

We could see that a smaller number comes before a larger number, so substract the smaller nummber from the bigger number, Or, the smaller number would be negative:

CM = 1000 - 100 =900 OR
= -100 + 1000 = 90

Adding all the values:

1000 + 900 + 30 +1 = 1931

Answer 3

1931

Answer 4

1931

Answer 5

1931 Plain and simplw stuff remember thawhen you do these the come out exactly how there are writen
M=1000c+100-1000+10+10+10-+1
I hope that thisa helps anytime you have a number that is higher then the one that they follow it is minused if higher then equal and it is the same foe equal numbers that get added. Good luck and best wishes

Answer 6

M = 1000
C = 100
CM = 900
X = 10
XXX = 30
I = 1

M + CM + XXX + I = 1000 + 900 + 30 + 1 = 1931

Answer 7

The year is 1931.
Here are how much each prefix equals.
M=1000
C=100
X=10
I=1

How to solve your problem is:
MCMXXXI
M = 1000
CM = 900 (1000-100)
XXX = 30 (10x3)
I = 1

1000+900+30+1= 1931

Answer 8

1969

Answer 9

That would be 1931 exactly.

Answer 10

MCM = 1900

XXXI = 31

So,
MCMXXXI = 1931