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4 answers

If it's an electric motor it's usually quite simple you measure the integral of the power consumed over a period of time Integral(V*A*dt) , measure the work done by the motor over the same time,something like integral(shaft torque*angular velocity*dt) and equate the difference to the amount of heat energy generated during that time - you might be a bit out as some of the energy probably went into vibration/noise/stray fields inducing currents in nearby conductors, which aren't strictly part of the heat equation you want (they'll eventually end up as an increase in temperature of something but maybe outside the bounds of the volume you are most interested in).

If it's something that burns fuel you can do more or less the same sort of thing as far as work done by the motor is concerned but it's trickier determining how much heat was generated by burning the fuel, lots of this disappears in exhaust gases, particularly for rockets and jets. Most of the calculations I have seen rely on some theoretical calculation (sometimes backed up by experiment) of the amount of energy typically released when, whatever volume of fuel, is burnt under those conditions. Whether you take the total amount of heat released into account or ignore the heat carried away in the exhaust seems to depend on whether you are interested in the total amount of energy released into the environment or how hot your motor and it's surroundings are likely to get.

Best of Luck- Mike

2006-09-24 22:31:30 · answer #1 · answered by Anonymous · 1 0

The simple answer is to subtract work out (kW) from work in. (kW). The remainder is kW losses due to:
1. Copper losses in the motor
2. Iron losses in the motor
3. Windage losses due to friction
Generally, a squirrel cage motor is better than 95% efficient. It is one of the most efficient means of power transfer.

2006-09-25 09:06:28 · answer #2 · answered by Bazza66 3 · 1 0

calculate the friction

2006-09-25 02:35:28 · answer #3 · answered by old_brain 5 · 0 0

thermometer

2006-09-25 02:28:40 · answer #4 · answered by Anonymous · 0 0

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