Using the digits 2, 3, 5, 6, and 8, find the smallest product?

Question

Sorry, I asked this questiona couple of days ago, but everybody gave me the wrong answer because I said that I thought it was 258x36 and they said I was correct when I didn't know if it was correct. So I guess everybody got a little confused.

But, I want to know how to get this answer in another way.
The teacher already taught us how to figure out the value of the numbers, like where you should put it and everything, but do you have another way to solve this problem? Thank you. :)

Whoops, forgot to add this.
Can you find a pattern so that, given any five distinct digits and using each digit only once, you could write down the smallest possible product of a 2-digit by 3-digit number?

I don't think many people understand my question.
Think of it this way, there are three boxes in the first line, and 2 boxes in the second line with the numbers 2, 3, 5, 6, and 8, to fill it in and you're supposed to multiply a 2 digit by 3 digit number using the digits provided.

Answer 1

240 is the smallest number that would include all of those number as divisors.

Answer 2

I didn't understand your question, find the smallest product is like 2*3*5*6*8= 1440

But if u meant that these numbers were denominators in fraction and u needed to find the smallest common multiple u should start by finding the prime product of each number

2= 2*1
3= 3*1
5= 5*1
6= 3*2*1
8= 2*2*2*1

Smallest product is: 1*2*2*2*3*5 = 120

Answer 3

i got 6630
85x26x3

Answer 4

6!! 2x3...