49?
2006-09-24 07:41:30
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answer #1
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answered by brownskin_283 2
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7
2006-09-24 07:50:11
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answer #2
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answered by prescott121 1
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Let L be the length
Let W be the width
now,
L = 3W
Area of rectangle is L x W = 147
Substituting L = 3W in above equation.
3W x W = 147
3WSquare = 147
Wsquare = 147/3
Wsquare = 49
so w =7
Answer 7
Cheers,
N
2006-09-24 07:52:05
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answer #3
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answered by shaumil n 1
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L=3W
LW=147
3WW=147
WW=49
W=7
2006-09-24 07:48:14
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answer #4
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answered by iyiogrenci 6
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A= L* W
L= 3W
147 = 3W(W)
441=W SQUARED
W=41
2006-09-24 07:53:33
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answer #5
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answered by zee 2
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W= x
L= 3x
A=L*W
A=3x*x
A=3x^2
147=3x^2
divide by 3
49= x^2
find the square root
7=x
W=7
L=21
2006-09-24 07:50:06
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answer #6
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answered by darth_loki 2
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Think of it this way:
L= 3w
W=
A= 147 sq ft
A= L*w
Soo.. lemme see if I can remember...
(3w)*w=A
A=147 sq ft.
I'll leave the rest for you to figure out.
<3
Stranger.
2006-09-24 07:48:57
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answer #7
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answered by Stranger 3
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