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can u please help me wiv this hw:
Work out the function of this sum and then do the inverse of it:
x- ->1/2x+3

2006-09-19 05:09:08 · 9 answers · asked by babi natalie 1 in Education & Reference Other - Education

9 answers

x-->(x-3) * 2

2006-09-19 05:19:00 · answer #1 · answered by gbiaki 2 · 0 0

13

2006-09-19 05:16:56 · answer #2 · answered by Yung Prince 2 · 0 0

27

2006-09-19 05:11:45 · answer #3 · answered by Anonymous · 0 0

i will attempt to describe the merely right i will: in the beginning, everytime you want to resolve for a variable (for this reason x), you will desire to positioned the variable on one area and the different numbers on the different. So first positioned the x on the left area of the equation. to try this, you will observe that x is unfavorable (-x). simply by this, to stability the equation, you upload constructive x to the two area: 5 + x = 8 - x + x Now, you already know that -x + x equals 0, so which you would be able to now take that out of the equation: 5 + x = 8 Now you will desire to positioned the 5 on the merely right area so x would be on my own. you already know that 5 is a favorable selection (+5), in an attempt to stability the equation, you subtract 5 on the two area: 5 - 5 + x = 8 - 5 5 - 5 equals 0, so which you would be able to now take that out of the equation: x = 8 - 5 you could now resolve x actually. x = 3 So this implies the suitable answer is x = 3 If we plug in 3 to the equation, we are going to se that it fairly is authentic. 5 = 8 - 3 5 = 5 i wish this helps =)

2016-12-15 10:36:30 · answer #4 · answered by vazid 4 · 0 0

what you have written doesn't make sense. Have another look at it, rewrite it and be more specific as to what you want.
x- ->1/2x+3 doesn't mean anything!

2006-09-19 05:32:35 · answer #5 · answered by joechuksy 3 · 0 0

Are you talking about integration and differentiation

2006-09-19 05:22:53 · answer #6 · answered by advent m 3 · 0 0

sorry, can't help you with that, but if you really wanted to do well on your homework you probably shouldn't be on the computer.

2006-09-23 04:49:16 · answer #7 · answered by Shanahan 1 · 0 0

Can you be a little more precise???

2006-09-19 05:32:19 · answer #8 · answered by Gandhi T. 2 · 0 0

I don't know!!

2006-09-19 05:16:43 · answer #9 · answered by leito 3 · 0 0

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