x-->(x-3) * 2
2006-09-19 05:19:00
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answer #1
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answered by gbiaki 2
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2006-09-19 05:16:56
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answer #2
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answered by Yung Prince 2
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2006-09-19 05:11:45
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answer #3
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answered by Anonymous
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i will attempt to describe the merely right i will: in the beginning, everytime you want to resolve for a variable (for this reason x), you will desire to positioned the variable on one area and the different numbers on the different. So first positioned the x on the left area of the equation. to try this, you will observe that x is unfavorable (-x). simply by this, to stability the equation, you upload constructive x to the two area: 5 + x = 8 - x + x Now, you already know that -x + x equals 0, so which you would be able to now take that out of the equation: 5 + x = 8 Now you will desire to positioned the 5 on the merely right area so x would be on my own. you already know that 5 is a favorable selection (+5), in an attempt to stability the equation, you subtract 5 on the two area: 5 - 5 + x = 8 - 5 5 - 5 equals 0, so which you would be able to now take that out of the equation: x = 8 - 5 you could now resolve x actually. x = 3 So this implies the suitable answer is x = 3 If we plug in 3 to the equation, we are going to se that it fairly is authentic. 5 = 8 - 3 5 = 5 i wish this helps =)
2016-12-15 10:36:30
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answer #4
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answered by vazid 4
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what you have written doesn't make sense. Have another look at it, rewrite it and be more specific as to what you want.
x- ->1/2x+3 doesn't mean anything!
2006-09-19 05:32:35
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answer #5
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answered by joechuksy 3
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Are you talking about integration and differentiation
2006-09-19 05:22:53
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answer #6
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answered by advent m 3
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sorry, can't help you with that, but if you really wanted to do well on your homework you probably shouldn't be on the computer.
2006-09-23 04:49:16
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answer #7
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answered by Shanahan 1
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Can you be a little more precise???
2006-09-19 05:32:19
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answer #8
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answered by Gandhi T. 2
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I don't know!!
2006-09-19 05:16:43
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answer #9
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answered by leito 3
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