Identical boxes are to be stacked along a back wall of a storage rom from floor to ceiling.
The backwall measures 12ft in length and 8ft. in height the boxes are 9X20. Which of the following estimates of the maximum number of boxes that can be stacked against the ENTIRE back wall?
A) 200
B) 70
C) 50
OR
D)15
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2006-09-18 16:49:32 · 10 answers · asked by i_luv_tar2 1 in Entertainment & Music ➔ Jokes & Riddles
144x96÷9x20=13824x180=76.8 Closes number is (B) 70
2006-09-18 17:15:09 · answer #1 · answered by Pepsi 4 · 0⤊ 0⤋
A
i am assuming the boxes are 9"x9"x20". If you put them so that the 9" sides are against the wall you get the most boxes in there against the wall. The wall area 12'x8' is 96 sq ft to be covered. With each box covering less than a square foot (9x9 = 81 sq in = 81/144 sq ft you will need more than 96 boxes. The only number greater than 96 is 200 so I chose that answer. Since speed counted I did not do all the fine detail artihmetic - I just eliminated the impossible answers.
2006-09-18 23:51:40 · answer #2 · answered by Rich Z 7 · 0⤊ 1⤋
70
2006-09-18 23:53:16 · answer #3 · answered by momoftwo 3 · 0⤊ 1⤋
I would guess 70
2006-09-18 23:52:41 · answer #4 · answered by iamigloo 6 · 0⤊ 1⤋
You can't 9X20 will not fit into 12X8
2006-09-18 23:53:51 · answer #5 · answered by delta s 4 · 0⤊ 1⤋
I hate math
2006-09-18 23:54:09 · answer #6 · answered by 4 strings 7 · 0⤊ 1⤋
answer is 50
2006-09-19 00:08:29 · answer #7 · answered by Anonymous · 0⤊ 0⤋
b
2006-09-18 23:54:06 · answer #8 · answered by crazeebitch2005 5 · 0⤊ 1⤋
C
2006-09-19 00:04:39 · answer #9 · answered by Albert 2 · 0⤊ 1⤋
C
2006-09-18 23:51:34 · answer #10 · answered by Mizz Latina 2 · 0⤊ 1⤋