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I already studied it back in college. Unfortunately, I already forgot all the formulas when I need them in my job now. Anybody got a reference on the internet?

2006-09-18 12:07:56 · 5 answers · asked by Optimus Prime 2 in Science & Mathematics Engineering

5 answers

Q = integral of (c*m*(dT))

integrate from low temperate limit T1 to high temperature limit T2

c - heat capacity (can depend on T)
m-mass
Q -heat
T-temperature

divide Q over the period of time interval t that you're interested in - that's cooling power, or cooling load.

google it, it's good nowdays.

2006-09-18 12:19:32 · answer #1 · answered by Snowflake 7 · 0 0

A falible memory is a poor substitute for logical thought. You better get your hands on a Mechanical Engineering Handbook right now.

If you're going to have to do this stuff all the time you might also order The ASHREA handbook for refrigeration. Unless you're a member their going to charge you out the Wazoo.

I kept all my textbooks, because I knew I wouldn't be able to remember all that stuff. At least I can look it up. An Engineer needs to have a reference materials handy. When you do the calculations you should record the reference you used in your calculations so next time you can see how you did it.

If you were my employee I'd have to beat you with a stick for not having reference materials handy.

2006-09-18 22:03:25 · answer #2 · answered by Roadkill 6 · 0 0

The engineering manual sublink in the web page given below gives you procedures about how to estimate loads on cleanrooms.

http://www.heatcraftrpd.com/service/handbooks.asp

If you search the web, you will get a free program about cold rooms from Keep Rite Refrigeration website.

2006-09-18 23:57:52 · answer #3 · answered by absolutezero 2 · 0 0

it's a bit complicated to explain here, but i use software now anyway. try wrightsoft.
where are you?

2006-09-18 19:16:59 · answer #4 · answered by something'srotten 4 · 0 0

Use your hand, does it feel cold?

2006-09-18 19:28:43 · answer #5 · answered by Courageous Capt. Cat 3 · 0 0

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