Explain how you find the domain, and how you get it's interval. Thank you!
2006-09-17 16:33:24 · 3 answers · asked by jose u 1 in Environment
Your equation is a bit ambiguous. I presume it's supposed to be:
sqrt(4-x^2)/sqrt(1-x^2)
The domain consists of all legal input values for x.
As you know, you can't take the square root of a negative number. Therefore, the numerator tells us (4-x^2) must be greater than or equal to zero. Therefore, -2 <= x <= 2
The denominator tells us (1-x^2) must be greater than zero.
(Note that it can't be exactly zero, otherwise sqrt(1-x^2) will be zero, and you have a zero in the denominator - and you're not allowed to divide by zero).
Therefore, -1 < x < 1
Values between -1 and -2, or between 1 and 2, don't work. They're okay for the numerator, but they'd give you a negative square root in the denominator.
Hence, the domain is -1 < x < 1.
2006-09-17 16:52:42 · answer #1 · answered by Bramblyspam 7 · 1⤊ 0⤋
this is a million. it isn't -a million. it really is termed the pricey sq. root, in basic terms the sq. root of a spread. The +/- difficulty in basic terms is on the marketplace in to play even as fixing an EQUATION, like x^2 = a million. in the experience that your instructor says the answer is +/- a million he/she is incorrect. this is in basic terms a million.
2016-11-27 21:05:36 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Ask this question in Mathematics, not Environment & Ecology.
2006-09-20 07:05:59 · answer #3 · answered by Amphibolite 7 · 0⤊ 0⤋