Does it increase your odds to buy multiple lottery tickets, and use random generated numbers.?

Question

Seems each new number has the same odds. However, if you use the SAME number on one ticket per week, you would increase the odds.

Answer 1

Simply put................yes.
Each set of numbers has the same odds, the odds decrease as you buy different sets sets of numbers.

For example, If you are using a 49 number, pick 6 system, each set of numbers has a 1 in 13,983,816 chance of winning
If you have 100 different sets of numbers, your chances are 1 in 139,838.2

So, if you have the money, and the time, and the jackpot is large enough, you can theoretically buy one ticket of each combination, and guarantee that you will win the lottery (but before you go to the bank and ask for a large lkoan to guarantee the lottery win...remember, the prize van be split and you may not be left with enough money to pay back the loan)


********Warning, for the mathematically inclined**************
There are mathematical formulas for calculating the odds
Using factorials, and order is not important

Using the previous function we can now calculate how many 6-number combinations are available in the 6/49 Let's assign some letters to the figures we'll be using:


d = drawn numbers = 6
t = total numbers = 49

C(t,d) = t!
d!x(t-d)!
= 49!
6!x43!
= 49x48x47x46x45x44
6x5x4x3x2x1
= 13,983,816

With 13,983,816 6-number combinations, the jackpot odds are 1 in 13,983,816

As all the numbers on the ticket are needed to get the jackpot, this will be the easiest result to calculate. However to calculate the lower prize combinations we have to reconsider the C function. We'll have to expand the function to recognise the winning numbers we pick in addition to the remaining numbers on our ticket, as the probability is calculated not just on the numbers that match but also on the numbers that don't.

Sounds confusing, so let's look at a new function that makes use of what we've learned so far to calculate the odds of getting a 3-Ball win:


d = drawn numbers
t = total range of numbers
m = matching numbers
C(d,m) = ways of matching m numbers from d drawn numbers
C(t-d,d-m) = combinations missed ticket numbers from the undrawn numbers
C(t,d) = total number of combinations

Pm = C(d,m) x C(t-d,d-m) C(6,3) = 6! C(43,3) = 43!
C(t,d) 3! x (6-3)! 3! x (43-3)!
= C(6,3) x C(49-6,6-3) = 720 = 43x42x41
C(49,6) 6 x 6 3x2x1
= C(6,3) x C(43,3) = 20 = 12341
13983816

Pm = 20x12341
13983816
= 1/57 (rounded up)


The 4-Ball prize odds can be calculated by substituting the relevant figures, you can even check the Pm function against the 6-Ball prize (0! = 1). However don't try the equation for the 5-Ball prize because there's something else we have to take into account - the Bonus Ball.

The 5-Ball prize is not just paid out for getting 5 matches, in fact it's for 5 matches and for not matching the Bonus Ball. If we work through the equation for a 5-Ball match, we'll eventually end up with the following result:


Pm = 258
13983816


We'll leave it at that stage to avoid any decimals just yet. Once the 6 main balls have been drawn there are 43 left in the pool. The chance of drawing the bonus ball at this stage is 1 in 43, and so we combine the 5-Ball probability with this figure to get the results we're after:


P(5 Ball+bonus) = 258x1 P(5 Ball-bonus) = 258x42
13983816x43 13983816x43
= 1/2330636 = 1/55492 (rounded up)


Finally, if you want to know the overall odds of winning, just add all the winning probabilities together:


1 + 1 + 1 + 1 + 1 = 1/54 (rounded up)
57 1033 55492 2330636 13983816

Answer 2

1

Answer 3

Using the same number on a ticket every week doesn't increase your odds because the results of one lottery doesn't depend on results of prior lotteries.

Of course the more lottery tickets you buy, the better the odds. However, the odds are so miniscule to begin with that buying a hundred tickets probably won't help much. My office has on a few occasions had an office pool where employees joined and both maybe around 80 tickets. But we got only $3 back (if we were lucky).

Answer 4

No, your odds are actually decreased (read further)

In the case of Canada's 6/49 or Great Britain's National Lottery (each set of numbers has about a 1 in 14 million chances of winning as cyrenaica stated earlier), buying multiple lottery tickets with different sets of random generated numbers actually DECREASES your odds and INCREASES your chances of winning

1 ticket = 1 in 14,000,000
100 tickets = 1 in 140,000


American Lotteries such as Mega Millions and Powerball operate on the same principle, but the odds of winning are much higher because more than 49 numbers are used, and the 'Mega Ball' and the 'Power Ball' are a different pick, but the same principle arises..............buy more tickets with different number combinations, decrease your odds, increase your chances of winning!

Bonne Chance!
.

Answer 5

I have always been fascinated with the lotto winners over the past years, especially the people who either hit it really big after years of playing, or the people who decide, on a whim, to buy a ticket this one time and hit. Most of the people who play for years when they hit something like Mega Millions say they play the same numbers on a regular basis, and are adamant about not getting random tickets or switching up their numbers.

There are sites with complex algorithms and different mathematical formulas out there, but when it comes down to it, it's a game of chance, the the odds are squarely against you, even if you buy a ton of tickets at the same time.

Answer 6

Obviously math in the US is in a sad state. Of course it increases your odds. It is very simple. There are a number of potential outcomes. With each ticket covering a differant outcome you increase your odds. Any idiot reading this and saying no he is wrong think of it this way pin head. The number of potential outcomes is a number and is not an infinite amount and so couldn't you buy enough tickets to cover every potential outcome and so be assured a winning ticket amongst the millions? Obviously you could. And so any small measure towards this end is increasing your odds. The problem is the number of potential outcomes is too great for you to profit in this way.

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Answer 7

run a spreadsheet on all the winning numbers since they started the numbers, pick your set of numbers and make sure they have never come up before play the same numbers each time till you win. Odds are in the area of 1 in 14 million, your more likley going to get hit by lightning

Remember Lotto is the governments way of taxing the poor. Your better off in the stock market

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Answer 10

Think of it like this: If your odds of winning the lottery are one in one million, then each ticket (even if it is the same number) has a one in one million chance of winning. Different numbers each have a one in one million chance of winning (using that ratio, of course).