2006-09-14 13:51:34 · 10 answers · asked by rock 1 in Consumer Electronics ➔ Other - Electronics
Your best bet is to go around to garage sales. Lots of people unloading their old VCRs and they work.
Added benifit--they are more like 10$.
2006-09-17 23:29:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Lets try cheaper than $30! How about FREE? It will be used, but, hey vhs tapes/vcrs are pretty much extinct. Check out Freecycle.org-
this website has a "group" in your city/town that you can join. It allows you to post Wanted : Free vcr in working good condition. If someone has one laying around they will post you back, and you arrange pick up w/them. You can also give up stuff you have laying around thats gathering dust. Thats there policy: everything must be offered or wanted FREE. NO money exhanged!!
Good luck! Also, yardsales, thrift stores, Walmart, Kmart, Target.
2006-09-14 21:05:07 · answer #2 · answered by truthbetold 3 · 0⤊ 0⤋
VCR's are not too populare anymore now that there are DVD's. You can buy a DVD player at Walmart for like $40 or even less, so I'm sure you could buy a VCR for less than $40 at either there or Kmart or something like that!
2006-09-14 21:03:29 · answer #3 · answered by speedy_me18 5 · 0⤊ 0⤋
Walmart!
2006-09-14 21:30:54 · answer #4 · answered by Aurthor D 4 · 0⤊ 0⤋
thats alot of money for a VCR but you should check out craiglist.com
2006-09-14 20:58:55 · answer #5 · answered by G.O.A.T. 6 · 0⤊ 0⤋
Target?
2006-09-14 21:11:42 · answer #6 · answered by Ximomila 2 · 0⤊ 0⤋
Walmart doesn't sell them anymore. According to this:
http://www.overstock.com/?PAGE=CATLIST&PRO_SUB_CAT=2166&PRO_SSUB_CAT=999&showQuality=0&CAT_SORTBY=1&CAT_SKUPAGE=60
it's going to cost at least $43.
2006-09-14 21:05:21 · answer #7 · answered by Electro-Fogey 6 · 0⤊ 0⤋
Try EBAY! PAWN SHOP! WALMART!
2006-09-14 21:30:12 · answer #8 · answered by sher7us 3 · 0⤊ 0⤋
did you try ebay?
2006-09-14 20:59:32 · answer #9 · answered by the_fatmanwalksalone 4 · 0⤊ 0⤋
WALMART!
2006-09-14 20:58:21 · answer #10 · answered by Sarah 4 · 0⤊ 0⤋