2006-09-12 14:36:24 · 4 answers · asked by Joel N 1 in Science & Mathematics ➔ Engineering
glycerine gravity is 1.258 g/cm^3
1 gallon (UK) = 4.546 l = 4.546 dm^3 = 4546 cm^3
1 gallon (US) = 3.785 l = 3.785 dm^3 = 3785 cm^3
so for UK is 1.258 * 4546* 50 = 285943 g = 286 kg
so for US is 1.258 * 3785* 50 = 238076 g = 238 kg
2006-09-12 14:58:01 · answer #1 · answered by fred 055 4 · 0⤊ 0⤋
Glycerine specific gravity is 1.258
So,density is=1.258 g/cm^3
density=mass/volume.
1 gallon (UK) = 4.546 l = 4546 cm^3
1 gallon (US) = 3.785 l = 3785 cm^3
so for 50 UK (gallon) 0f glucerine, its weight
= 1.258 * 4546* 50
= 285943 g
= 286 kg
so for 50 US gallon of glycerene, its weight
= 1.258 * 3785* 50
= 238076 g
= 238 kg
2006-09-13 07:18:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1.258 times as much as 50 gallons of water
2006-09-12 16:00:55 · answer #3 · answered by iberius 4 · 0⤊ 0⤋
50x10x1.258=629lb.
2006-09-12 18:46:58 · answer #4 · answered by zee_prime 6 · 0⤊ 0⤋