This question is for someone who answered another question? I'm just wondering?????
2006-09-12 09:06:06 · 11 answers · asked by dmgoldsbo7 3 in Politics & Government ➔ Law Enforcement & Police
Oh cool another point from the DDD of the week!! Thanks again.
Yes this is another question that makes no sense. Is this question for someone specific??
2006-09-15 20:12:25 · answer #1 · answered by deputeesteph33 3 · 0⤊ 0⤋
My sister has had 3 and the time served was not in jail. She had to pay a whole lot of cash! She had to attend regular AA meetings and she had to have a Breathalyzer installed in her car.
She can go to jail if she is a passenger in a car where folks have been drinking, even if she is sober.
Seems like jail would have been the easier solution. My sister is also the "signer" for my mom who is in a nursing home from a stroke. Maybe they allowed her to suffer in the real world rather than jail??
2006-09-12 16:13:35 · answer #2 · answered by mauihillside 3 · 0⤊ 0⤋
Expensive Attorney
2006-09-12 16:12:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The person may have been related to someone influential or even another judge in that jurisdiction.
Corruption still exists in some states - albeit on a lower level.
2006-09-12 16:11:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋
If it was your first offense you'll most likely go away with a fine... they really come down on repeat offenders though...
2006-09-12 16:11:38 · answer #5 · answered by sarahbeth 4 · 0⤊ 0⤋
Usually it's the rich suburbanites.
2006-09-12 17:03:42 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I think in most states ,2ND. offence is 10 day and 3rd. offence is 30 day.
2006-09-12 16:09:23 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Only if you are really wealthy, being famous certainly helps as well.
2006-09-12 16:07:49 · answer #8 · answered by cognitively_dislocated 5 · 0⤊ 0⤋
yes
2006-09-14 20:11:29 · answer #9 · answered by Anonymous · 0⤊ 0⤋
You will fail the bar.
Now bring me a gin & tonic.
2006-09-12 16:13:42 · answer #10 · answered by Dip Shït 2 · 1⤊ 0⤋