general equation: Ax^2+Ay^2+Cx+Dy+E=0 , A not= 0
Show that the center of the circle is the point
(h,k)= (-C/2A , -D/2A)
I don't mind even if you dont answer, but can you give some hints? maybe some solutions?
2006-09-11 22:45:43 · 3 answers · asked by Lorenz 2 in Education & Reference ➔ Homework Help
show also that the squre of the radius is
r^2= C^2+D^2-4AE / 4A^2
Apply then determine the center and radius of a circle with: 3x^2 + 3y^2 - 12x + 6y - 60=0
Verify you answer
(you dont have to tell my the answers, hints are okay)
2006-09-11 23:15:50 · update #1
I used to be an expert in that kind of geometry :-(
But that was a long time ago (1.5 years :-P)
Anyway, I didnt know Homonculuses did math.
Just use your powers :-P
2006-09-11 22:54:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
OMG I am SO glad I am not in school these days!!! I would FAIL miserably.
My 2 older kids are ON THEIR OWN in math! I can do 1st grade math - so far that is! LOL
2006-09-12 05:48:39 · answer #2 · answered by jennifersuem 7 · 0⤊ 1⤋
oooooooooooooooooooo
2006-09-12 05:51:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋