a train of mass 10^7 N is running on a level track with uniform speed of 36km/h. the frictional force is 0.5 kgf per quintal. What is the power of the engine?
ans- 500KW
2006-09-11 22:41:09 · 9 answers · asked by sweepie 2 in Science & Mathematics ➔ Physics
You sure do have quite a few questions relating to physics problems... I am sure there are people here that are willing to answer them, but please try getting a tutor.
It's not just because I want you to stop asking these questions, but I think it would be beneficial for yourself if you learned how to find your way through such equations. It's much more rewarding to know that we can solve things on our own without somebody there to guide us and hold our hand all the way through.
2006-09-11 22:49:23 · answer #1 · answered by donatello 3 · 0⤊ 0⤋
This question csn be solved if it is starting from rest.
now f=0.5Kgf/100kg so net f=0.5/100*massof train
mass of train=10^6 so f=0.5*10^4 or 5*10^3
now p=E/t or p=F*dx/dt or p=F*v
v=36km/hr=10km/sec
so p=5000*10 =5*10^4w=50kw
I think ans is wrong and if I am wrong please send an solution with the help of e-mail
My e-mail id is mahaveersoganiappu@yahoo.com
2006-09-12 12:53:06 · answer #2 · answered by mahaveersoganiappu 2 · 0⤊ 0⤋
Insufficient Data to Solve!!!
know wonder,---- This is somewhat of a trick Question
It doesn't really take much to solve it if all the information where there ----- The trick is to SEE the CONVERSION of the Units that are there , that's what this problem is trying to strengthen in YOUR minds capabilities. Once converted it is a fairly easy question.
Now get to School!!!
jejejejejejejeje
2006-09-13 22:20:48 · answer #3 · answered by joey 2 · 0⤊ 0⤋
If speed is constant, then the train won't accelerate. Since frictional force is given, you need to accelerate to overcome this friction if you want to maintain constant velocity. How much is that acceleration?
Data insufficient.
2006-09-12 05:59:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
dont ask me to sit and do the job that your tutor is to do
2006-09-16 02:55:05 · answer #5 · answered by V.D. 1 · 0⤊ 0⤋
go to school
2006-09-12 14:47:35 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Do your homework yourself
2006-09-12 05:42:43 · answer #7 · answered by astrokid 4 · 1⤊ 0⤋
the best way to do it... is to get off of yahoo and do your damn homework...
2006-09-12 12:20:58 · answer #8 · answered by Ferrasoca 1 · 0⤊ 0⤋
So, it is called physics, great.
2006-09-12 05:56:52 · answer #9 · answered by Mani G.India 4 · 0⤊ 0⤋