the formula is that
x^2-y^2=(x+y)*(x-y)
2006-09-11 21:52:09
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answer #1
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answered by Anonymous
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The difference of two squares rule is that if you have an equation in which one square is subtracted from another square, you can factor it so that one second term is positive, the other negative:
x^2-y^2 = (x+y)(x-y)
When you recombine them, you get the original equation:
(x+y)(x-y) = x^2 +xy -xy -y^2 = x^2-y^2.
On the other hand with the sum of two squares, such as x^2+y^2, you cannot factor it in the same way and then recombine the factors to return to your original equation. Consider:
x^2+y^2 = (x+y)(x+y)
Now recombine them:
(x+y)(x+y) = x^2+xy+y+y^2 = x^2 + 2xy + y^2.
Thus x^2+y^2 is said to be unfactorable (at least for a beginning algebra student, I won't know for sure for a couple years).
Good luck!
I hope this helps
2006-09-12 08:39:45
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answer #2
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answered by ronw 4
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if you had
a^2 - b^2
if would always equal
(a-b) x (a+b)
which would be the difference of two squares
2006-09-12 04:39:24
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answer #3
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answered by Aslan 6
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ax^2 - by^2 = (sqrt(a)x - sqrt(b)y)(sqrt(a)x + sqrt(b)y)
if its x^2 - y^2, then this would be (x - y)(x + y)
if its ax^2 - b, then just leave out the y's in the top answer.
2006-09-12 04:03:23
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answer #4
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answered by Sherman81 6
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